What is (\partial)/(\partial x)(cos^2(x+y)) ?

The answer to (\partial)/(\partial x)(cos^2(x+y)) is -sin(2(x+y))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(cos^2(x+y))

\frac{\partial}{\partial x} (cos^{2} (x + y))

- sin (2 (x + y))

Solution steps

\frac{\partial}{\partial x} (cos^{2} (x + y))

Treat

y

as a constant

Apply the chain rule:

2 cos (x + y) \frac{\partial}{\partial x} (cos (x + y))

= 2 cos (x + y) \frac{\partial}{\partial x} (cos (x + y))

\frac{\partial}{\partial x} (cos (x + y)) = - sin (x + y)

= 2 cos (x + y) (- sin (x + y))

Simplify

2 cos (x + y) (- sin (x + y)) : - sin (2 (x + y))

= - sin (2 (x + y))

\frac{d y}{d x} + \frac{2 y}{x} = \frac{1}{x ^{2}}

x^{2} - 4, y = 0, x = - 4, x = 3

\frac{d}{d x} (ln (\frac{a + b x}{a - b x}))

\frac{1}{s ^{2} + 4 s + 12}

\frac{d}{d x} ((7 x + 3)^{2})

What is (\partial)/(\partial x)(cos^2(x+y)) ?
The answer to (\partial)/(\partial x)(cos^2(x+y)) is -sin(2(x+y))