What is the solution for (dy)/(dx)=sqrt(y^2-9) ?

The solution for (dy)/(dx)=sqrt(y^2-9) is y= 3/(2e^{x+c_{1)}}+(3e^{x+c_{1}})/2

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(dy)/(dx)=sqrt(y^2-9)

\frac{d y}{d x} = y^{2} - 9

y = \frac{3}{2 e ^{x + c_{1}}} + \frac{3 e ^{x + c_{1}}}{2}

Solution steps

\frac{d y}{d x} = y^{2} - 9

Solve separable ODE:

y = \frac{3}{2 e ^{x + c_{1}}} + \frac{3 e ^{x + c_{1}}}{2}

y = \frac{3}{2 e ^{x + c_{1}}} + \frac{3 e ^{x + c_{1}}}{2}

\int \frac{ln ( t )}{3} d t

\int \frac{x}{( x + 3 ) ^{5}} d x

\int (x + 1) sin (2 x - 3) d x

y^{^{''}} - 20 y^{^{'}} + 181 y = 0

\int (x^{2} - 5)^{2} d x

What is the solution for (dy)/(dx)=sqrt(y^2-9) ?
The solution for (dy)/(dx)=sqrt(y^2-9) is y= 3/(2e^{x+c_{1)}}+(3e^{x+c_{1}})/2