What is the derivative of-sin(2x*2+cos(2x)*2) ?

The derivative of-sin(2x*2+cos(2x)*2) is -4cos(2x)-4sin(2x)

What is the first derivative of-sin(2x*2+cos(2x)*2) ?

The first derivative of-sin(2x*2+cos(2x)*2) is -4cos(2x)-4sin(2x)

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\frac{d}{d x} (- sin (2 x) \cdot 2 + cos (2 x) \cdot 2)

- 4 cos (2 x) - 4 sin (2 x)

Solution steps

\frac{d}{d x} (- sin (2 x) \cdot 2 + cos (2 x) \cdot 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (sin (2 x) \cdot 2) + \frac{d}{d x} (cos (2 x) \cdot 2)

\frac{d}{d x} (sin (2 x) \cdot 2) = 4 cos (2 x)

\frac{d}{d x} (cos (2 x) \cdot 2) = - 4 sin (2 x)

= - 4 cos (2 x) - 4 sin (2 x)

\int x^{2} - 7 x + 8 d x

- 3 x^{2} + 6 x + 4

n = 1 \sum \infty n^{5} (1 + n^{6})^{1}

What is the derivative of-sin(2x*2+cos(2x)*2) ?
The derivative of-sin(2x*2+cos(2x)*2) is -4cos(2x)-4sin(2x)
What is the first derivative of-sin(2x*2+cos(2x)*2) ?
The first derivative of-sin(2x*2+cos(2x)*2) is -4cos(2x)-4sin(2x)