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Popular Calculus >

derivative of-sin(2x2+cos(2x)2)

Solution

\frac{d}{d x} (- sin (2 x) \cdot 2 + cos (2 x) \cdot 2)

Solution

- 4 cos (2 x) - 4 sin (2 x)

Solution steps

\frac{d}{d x} (- sin (2 x) \cdot 2 + cos (2 x) \cdot 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (sin (2 x) \cdot 2) + \frac{d}{d x} (cos (2 x) \cdot 2)

\frac{d}{d x} (sin (2 x) \cdot 2) = 4 cos (2 x)

\frac{d}{d x} (cos (2 x) \cdot 2) = - 4 sin (2 x)

= - 4 cos (2 x) - 4 sin (2 x)

Graph

Popular Examples

tangent of-3x^2+6x+4

t an g e n t - 3 x^{2} + 6 x + 4

derivative of f(x)=2e^x+2/(\sqrt[3]{x)}

d er i v a t i v e f (x) = 2 e^{x} + \frac{2}{3 x}

sum from n=1 to infinity of n^5(1+n^6)^1

n = 1 \sum \infty n^{5} (1 + n^{6})^{1}

integral of (z^3)/(\sqrt[3]{5+z^4)}

\int \frac{z ^{3}}{3 5 + z ^{4}} d z

\frac{d y}{d x} = 5 - y

Frequently Asked Questions (FAQ)

What is the derivative of-sin(2x*2+cos(2x)*2) ?
The derivative of-sin(2x*2+cos(2x)*2) is -4cos(2x)-4sin(2x)
What is the first derivative of-sin(2x*2+cos(2x)*2) ?
The first derivative of-sin(2x*2+cos(2x)*2) is -4cos(2x)-4sin(2x)