What is the derivative of f(x)=3(x)^3+cos(x) ?

The derivative of f(x)=3(x)^3+cos(x) is 9x^2-sin(x)

What is the first derivative of f(x)=3(x)^3+cos(x) ?

The first derivative of f(x)=3(x)^3+cos(x) is 9x^2-sin(x)

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derivative of

f (x) = 3 (x)^{3} + cos (x)

9 x^{2} - sin (x)

Solution steps

\frac{d}{d x} (3 x^{3} + cos (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{3}) + \frac{d}{d x} (cos (x))

\frac{d}{d x} (3 x^{3}) = 9 x^{2}

\frac{d}{d x} (cos (x)) = - sin (x)

= 9 x^{2} - sin (x)

\int sin^{2020} (d) x d x

\frac{d}{d x} (- sin (3 x) 3)

\int (2 x + 1)^{- 1} d x

x \to + 0 lim (\frac{2 sin ( 2 x )}{x})

What is the derivative of f(x)=3(x)^3+cos(x) ?
The derivative of f(x)=3(x)^3+cos(x) is 9x^2-sin(x)
What is the first derivative of f(x)=3(x)^3+cos(x) ?
The first derivative of f(x)=3(x)^3+cos(x) is 9x^2-sin(x)