What is inverse oflaplace (-3)/((s-2)^2) ?

The answer to inverse oflaplace (-3)/((s-2)^2) is -3e^{2t}t

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse oflaplace (-3)/((s-2)^2)

inverse laplace

\frac{- 3}{( s - 2 ) ^{2}}

- 3 e^{2 t} t

Solution steps

L^{- 1} {\frac{- 3}{( s - 2 ) ^{2}}}

Apply inverse transform rule:

L^{- 1} {F (s)} = f (t)

then

L^{- 1} {F (s - a)} = e^{a t} f (t)

For

\frac{- 3}{( s - 2 ) ^{2}} : a = 2, F (s) = \frac{- 3}{s ^{2}}

= e^{2 t} L^{- 1} {\frac{- 3}{s ^{2}}}

L^{- 1} {\frac{- 3}{s ^{2}}} : - 3 t

= - 3 e^{2 t} t

\frac{d}{d x} (x^{4} - x^{2})

\int tan (5 x) d x

\frac{d}{d x} (\frac{x ^{2} - 2 x + 5}{x ^{2} + 9})

\int (- \frac{3}{10 - 10 x ^{2}}) d x

y = 3 tan (2 x)

What is inverse oflaplace (-3)/((s-2)^2) ?
The answer to inverse oflaplace (-3)/((s-2)^2) is -3e^{2t}t