What is the integral of x/(x^4+49) ?

The integral of x/(x^4+49) is 1/14 arctan((x^2)/7)+C

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integral of x/(x^4+49)

\int \frac{x}{x ^{4} + 49} d x

\frac{1}{14} arctan (\frac{x ^{2}}{7}) + C

Solution steps

\int \frac{x}{x ^{4} + 49} d x

Apply u-substitution

: \int \frac{1}{2 ( u ^{2} + 49 )} d u

= \int \frac{1}{2 ( u ^{2} + 49 )} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int \frac{1}{u ^{2} + 49} d u

Apply Integral Substitution

= \frac{1}{2} \cdot \int \frac{1}{7 ( v ^{2} + 1 )} d v

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \frac{1}{7} \cdot \int \frac{1}{v ^{2} + 1} d v

Use the common integral:

\int \frac{1}{v ^{2} + 1} d v = arctan (v)

= \frac{1}{2} \cdot \frac{1}{7} arctan (v)

Substitute back

= \frac{1}{2} \cdot \frac{1}{7} arctan (\frac{x ^{2}}{7})

Simplify

\frac{1}{2} \cdot \frac{1}{7} arctan (\frac{x ^{2}}{7}) : \frac{1}{14} arctan (\frac{x ^{2}}{7})

= \frac{1}{14} arctan (\frac{x ^{2}}{7})

Add a constant to the solution

= \frac{1}{14} arctan (\frac{x ^{2}}{7}) + C

x \to 2 - lim (\frac{5 x}{x - 2})

(x + i y)^{2}

y^{^{'}} + (\frac{2}{x}) y = 0

\int (\frac{1 - x}{x})^{2} d x

f (x) = 5 + 5 x^{2} - 2 x^{3}, at x = 2

What is the integral of x/(x^4+49) ?
The integral of x/(x^4+49) is 1/14 arctan((x^2)/7)+C