What is (\partial)/(\partial x)(30x^5y^4-20x^4y^3) ?

The answer to (\partial)/(\partial x)(30x^5y^4-20x^4y^3) is 150y^4x^4-80y^3x^3

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(\partial)/(\partial x)(30x^5y^4-20x^4y^3)

\frac{\partial}{\partial x} (30 x^{5} y^{4} - 20 x^{4} y^{3})

150 y^{4} x^{4} - 80 y^{3} x^{3}

Solution steps

\frac{\partial}{\partial x} (30 x^{5} y^{4} - 20 x^{4} y^{3})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (30 x^{5} y^{4}) - \frac{\partial}{\partial x} (20 x^{4} y^{3})

\frac{\partial}{\partial x} (30 x^{5} y^{4}) = 150 y^{4} x^{4}

\frac{\partial}{\partial x} (20 x^{4} y^{3}) = 80 y^{3} x^{3}

= 150 y^{4} x^{4} - 80 y^{3} x^{3}

x \to - 2 lim (\frac{1}{x ^{2}})

x^{2} + y^{2} = 169, (12, - 5)

\frac{d}{d x} ((4 x - 13) ln ((2 x - 7) (x - 3)))

\int_{- 2}^{3} (8 z^{3} + 3 z - 1) d z

\int_{1}^{\infty} \frac{( e ^{- x} )}{x} d x

What is (\partial)/(\partial x)(30x^5y^4-20x^4y^3) ?
The answer to (\partial)/(\partial x)(30x^5y^4-20x^4y^3) is 150y^4x^4-80y^3x^3