What is the tangent of g(x)=3sqrt(x),\at x=4 ?

The tangent of g(x)=3sqrt(x),\at x=4 is y= 3/4 x+3

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tangent of g(x)=3sqrt(x),\at x=4

tangent of

g (x) = 3 x, at x = 4

y = \frac{3}{4} x + 3

Solution steps

Find the tangent point:

(4, 6)

Find the slope of

g (x) = 3 x : \frac{d g ( x )}{d x} = \frac{3}{2 x}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{3}{4}

Find the line with slope m=

\frac{3}{4}

and passing through

(4, 6) : y = \frac{3}{4} x + 3

y = \frac{3}{4} x + 3

y

\frac{d}{d x} (\frac{( - 3 x ^{2} )}{( ( x ^{2} - 2 x + 1 ) )})

\int_{1}^{\infty} \frac{x}{9 + x ^{2}} d x

\int 1 + tan^{2} (x) d x

x \to 2 lim (\frac{g ( x )}{h ( x )})

What is the tangent of g(x)=3sqrt(x),\at x=4 ?
The tangent of g(x)=3sqrt(x),\at x=4 is y= 3/4 x+3