What is the derivative of-3/(16x^{7/4}) ?

The derivative of-3/(16x^{7/4}) is (21)/(64x^{11/4)}

What is the first derivative of-3/(16x^{7/4}) ?

The first derivative of-3/(16x^{7/4}) is (21)/(64x^{11/4)}

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\frac{d}{d x} (- \frac{3}{16 x ^{\frac{7}{4}}})

\frac{21}{64 x ^{\frac{11}{4}}}

Solution steps

\frac{d}{d x} (- \frac{3}{16 x ^{\frac{7}{4}}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{3}{16} \frac{d}{d x} (\frac{1}{x ^{\frac{7}{4}}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= - \frac{3}{16} \frac{d}{d x} (x^{- \frac{7}{4}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - \frac{3}{16} (- \frac{7}{4} x^{- \frac{7}{4} - 1})

Simplify

- \frac{3}{16} (- \frac{7}{4} x^{- \frac{7}{4} - 1}) : \frac{21}{64 x ^{\frac{11}{4}}}

= \frac{21}{64 x ^{\frac{11}{4}}}

ln (9 - 2 x)

\frac{d}{d x} (\frac{1}{3 x + 5})

\int_{1}^{2} x d x

\frac{d}{d x} ([x + (x + sin^{2} (x))^{7}]^{4})

\frac{\partial}{\partial x} (cos^{3} (x^{3} y^{8}))

What is the derivative of-3/(16x^{7/4}) ?
The derivative of-3/(16x^{7/4}) is (21)/(64x^{11/4)}
What is the first derivative of-3/(16x^{7/4}) ?
The first derivative of-3/(16x^{7/4}) is (21)/(64x^{11/4)}