What is the solution for y^'+2y=35sin(t)+35cos(t) ?

The solution for y^'+2y=35sin(t)+35cos(t) is y=7cos(t)+21sin(t)+(c_{1})/(e^{2t)}

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y^'+2y=35sin(t)+35cos(t)

y^{^{'}} + 2 y = 35 sin (t) + 35 cos (t)

y = 7 cos (t) + 21 sin (t) + \frac{c _{1}}{e ^{2 t}}

Solution steps

y^{'} (t) + 2 y = 35 sin (t) + 35 cos (t)

Solve linear ODE:

y = 7 cos (t) + 21 sin (t) + \frac{c _{1}}{e ^{2 t}}

y = 7 cos (t) + 21 sin (t) + \frac{c _{1}}{e ^{2 t}}

\frac{d y}{d x}, x + y = 1

x = - 2 y^{2} - 4 y + 1, x = y^{2} + 8 y + 10

\frac{\partial}{\partial x} (e^{3 x yz - 8})

(- 2, - 10), (0, - 4)

\frac{d}{d x} (\frac{4 x}{x ^{2} + 7})

What is the solution for y^'+2y=35sin(t)+35cos(t) ?
The solution for y^'+2y=35sin(t)+35cos(t) is y=7cos(t)+21sin(t)+(c_{1})/(e^{2t)}