What is the derivative of x^3sec(x) ?

The derivative of x^3sec(x) is 3x^2sec(x)+sec(x)tan(x)x^3

What is the first derivative of x^3sec(x) ?

The first derivative of x^3sec(x) is 3x^2sec(x)+sec(x)tan(x)x^3

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\frac{d}{d x} (x^{3} sec (x))

3 x^{2} sec (x) + sec (x) tan (x) x^{3}

Solution steps

\frac{d}{d x} (x^{3} sec (x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{3}, g = sec (x)

= \frac{d}{d x} (x^{3}) sec (x) + \frac{d}{d x} (sec (x)) x^{3}

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (sec (x)) = sec (x) tan (x)

= 3 x^{2} sec (x) + sec (x) tan (x) x^{3}

x \to - \frac{1}{3} lim (9 x (4 x + 9)^{2})

\int (\frac{9}{x}) d x

arccsc (- 9 t^{2})

\int \frac{x + 7}{x ^{2} + 9} d x

\int \frac{1}{v ^{2}} d v

What is the derivative of x^3sec(x) ?
The derivative of x^3sec(x) is 3x^2sec(x)+sec(x)tan(x)x^3
What is the first derivative of x^3sec(x) ?
The first derivative of x^3sec(x) is 3x^2sec(x)+sec(x)tan(x)x^3