What is (\partial)/(\partial x)(cos(8y-3x)) ?

The answer to (\partial)/(\partial x)(cos(8y-3x)) is 3sin(8y-3x)

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(\partial)/(\partial x)(cos(8y-3x))

\frac{\partial}{\partial x} (cos (8 y - 3 x))

3 sin (8 y - 3 x)

Solution steps

\frac{\partial}{\partial x} (cos (8 y - 3 x))

Treat

y

as a constant

Apply the chain rule:

- sin (8 y - 3 x) \frac{\partial}{\partial x} (8 y - 3 x)

= - sin (8 y - 3 x) \frac{\partial}{\partial x} (8 y - 3 x)

\frac{\partial}{\partial x} (8 y - 3 x) = - 3

= - sin (8 y - 3 x) (- 3)

Simplify

= 3 sin (8 y - 3 x)

\frac{d}{d x} (\frac{1}{2} (cos (5 x))^{2})

y^{^{''}} - 2 y^{^{'}} = 12 x - 10

3 x^{2} + 2 x

x^{2} - 4, 5

\int_{1}^{2} x^{3} + \frac{1}{4 x ^{3}} d x

What is (\partial)/(\partial x)(cos(8y-3x)) ?
The answer to (\partial)/(\partial x)(cos(8y-3x)) is 3sin(8y-3x)