What is the tangent of f(x)=x^2+3x+4pi,\at x=-3 ?

The tangent of f(x)=x^2+3x+4pi,\at x=-3 is y=-3x+4pi-9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=x^2+3x+4pi,\at x=-3

tangent of

f (x) = x^{2} + 3 x + 4 π, at x = - 3

y = - 3 x + 4 π - 9

Solution steps

Find the tangent point:

(- 3, 4 π)

Find the slope of

f (x) = x^{2} + 3 x + 4 π : \frac{df ( x )}{d x} = 2 x + 3

Compute the slope of

f (x) = x^{2} + 3 x + 4 π

x = - 3 : m = - 3

Find the line with slope m=

- 3

and passing through

(- 3, 4 π) : y = - 3 x + 4 π - 9

y = - 3 x + 4 π - 9

\frac{d}{d x} (arccos (\frac{x}{b}))

\frac{d ^{4}}{d x ^{4}} (\frac{8 x}{1 - x})

f (x) = 5^{5 x + 1} + 3^{1 - 3 x}

y^{^{'}} + 5 y = 7

\frac{d ^{2}}{d x ^{2}} (- 2 x^{4} - 2 x^{3} + 60 x^{2} - 22)

What is the tangent of f(x)=x^2+3x+4pi,\at x=-3 ?
The tangent of f(x)=x^2+3x+4pi,\at x=-3 is y=-3x+4pi-9