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Popular >

y^'+5y=7

Solution

y^{^{'}} + 5 y = 7

Solution

y = - \frac{e ^{- 5 t - c_{1}}}{5} + \frac{7}{5}

Solution steps

y^{'} (t) + 5 y = 7

Solve separable ODE:

y = - \frac{e ^{- 5 t - c_{1}}}{5} + \frac{7}{5}

y = - \frac{e ^{- 5 t - c_{1}}}{5} + \frac{7}{5}

Popular Examples

(d^2)/(dx^2)(-2x^4-2x^3+60x^2-22)

\frac{d ^{2}}{d x ^{2}} (- 2 x^{4} - 2 x^{3} + 60 x^{2} - 22)

derivative of 2xcos(x-2sin(x))

\frac{d}{d x} (2 x cos (x) - 2 sin (x))

tangent of x/(1+x^2),\at x=2 tangent of

\frac{x}{1 + x ^{2}}, at x = 2

integral of 0.02e^x

\int 0.02 e^{x} d x

2xy^2+4=2(3-x^2y)y^',y(-1)=8

2 x y^{2} + 4 = 2 (3 - x^{2} y) y^{^{'}}, y (- 1) = 8

Frequently Asked Questions (FAQ)

What is the solution for y^'+5y=7 ?
The solution for y^'+5y=7 is y=-(e^{-5t-c_{1}})/5+7/5