What is the integral of 7/(x(ln(x))^2) ?

The integral of 7/(x(ln(x))^2) is -7/(ln(x))+C

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integral of 7/(x(ln(x))^2)

\int \frac{7}{x ( ln ( x ) ) ^{2}} d x

- \frac{7}{ln ( x )} + C

Solution steps

\int \frac{7}{x ( ln ( x ) ) ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 7 \cdot \int \frac{1}{x ( ln ( x ) ) ^{2}} d x

Apply u-substitution

: \int \frac{1}{u ^{2}} d u

= 7 \cdot \int \frac{1}{u ^{2}} d u

Apply the Power Rule

: - \frac{1}{u}

= 7 (- \frac{1}{u})

Substitute back

u = ln (x)

= 7 (- \frac{1}{ln ( x )})

Simplify

7 (- \frac{1}{ln ( x )}) : - \frac{7}{ln ( x )}

= - \frac{7}{ln ( x )}

Add a constant to the solution

= - \frac{7}{ln ( x )} + C

y = \frac{8}{x}

x \to 0 lim (2 x^{2} ln (x))

\frac{d}{d x} (5 \frac{5 x}{4 x - 3})

x \to 0 lim ([x] \cdot sin (\frac{1}{x}))

\int \frac{7 x ^{2} + 8 x - 2}{x ^{2} + 2 x} d x

What is the integral of 7/(x(ln(x))^2) ?
The integral of 7/(x(ln(x))^2) is -7/(ln(x))+C