What is the derivative of 3x^2-2x ?

The derivative of 3x^2-2x is 6x-2

What is the first derivative of 3x^2-2x ?

The first derivative of 3x^2-2x is 6x-2

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derivative of

3 x^{2} - 2 x

6 x - 2

Solution steps

\frac{d}{d x} (3 x^{2} - 2 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) - \frac{d}{d x} (2 x)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (2 x) = 2

= 6 x - 2

7 (4^{x})

x \to - 5 - lim (\frac{1}{x ^{2} - 25})

\frac{d}{d t} (\frac{5 t}{1 + 2 t ^{2}})

\frac{d y}{d t} = \frac{1}{( y + 1 ) ( t - 2 )}, y (0) = 0

\int cos (5 x) cos (10 x) d x

What is the derivative of 3x^2-2x ?
The derivative of 3x^2-2x is 6x-2
What is the first derivative of 3x^2-2x ?
The first derivative of 3x^2-2x is 6x-2