What is the solution for y^2e^t+(e^t+2)y^'=0 ?

The solution for y^2e^t+(e^t+2)y^'=0 is y=-1/(-ln(e^t+2)+c_{1)}

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y^2e^t+(e^t+2)y^'=0

y^{2} e^{t} + (e^{t} + 2) y^{^{'}} = 0

y = - \frac{1}{- ln ( e ^{t} + 2 ) + c _{1}}

Solution steps

y^{2} e^{t} + (e^{t} + 2) y^{'} (t) = 0

Solve separable ODE:

y = - \frac{1}{- ln ( e ^{t} + 2 ) + c _{1}}

y = - \frac{1}{- ln ( e ^{t} + 2 ) + c _{1}}

\int \frac{x ^{2} + 4 x - 5}{( x ^{2} - 9 ) ( x + 1 )} d x

x \to \infty lim (0^{x})

x^{4} (e^{x})

4 sin^{2} (t)

\frac{\partial}{\partial y} (cos (z))

What is the solution for y^2e^t+(e^t+2)y^'=0 ?
The solution for y^2e^t+(e^t+2)y^'=0 is y=-1/(-ln(e^t+2)+c_{1)}