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Popular >

y^'+ay=b

Solution

y^{^{'}} + a y = b

Solution

y = - \frac{e ^{- a t - c_{1} a}}{a} + \frac{b}{a}

Solution steps

y^{'} (t) + a y (t) = b

Solve separable ODE:

y = - \frac{e ^{- a t - c_{1} a}}{a} + \frac{b}{a}

y = - \frac{e ^{- a t - c_{1} a}}{a} + \frac{b}{a}

Graph

Popular Examples

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\frac{d}{d x} (\frac{14 x + x ^{2}}{( 7 + x ) ^{2}})

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\int cot (x) d x

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\int_{0}^{\frac{7}{2}} (2 x + 1)^{- \frac{1}{3}} d x

longdivision (3x+2)/(5x-1)long division

\frac{3 x + 2}{5 x - 1}

(\partial)/(\partial z)(x^2+z^2)

\frac{\partial}{\partial z} (x^{2} + z^{2})

Frequently Asked Questions (FAQ)

What is the solution for y^'+ay=b ?
The solution for y^'+ay=b is y=-(e^{-at-c_{1}a})/a+b/a