What is derivative of f(x)=(40t)/(t+2) ?

The answer to derivative of f(x)=(40t)/(t+2) is (dt)/(dx)=0

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derivative of f(x)=(40t)/(t+2)

derivative of

f (x) = \frac{40 t}{t + 2}

\frac{d t}{d x} = 0

Solution steps

f (x) = \frac{40 t}{t + 2}

Treat

t

t (x)

Differentiate both sides:

0 = \frac{80 \frac{d t}{d x}}{( t + 2 ) ^{2}}

Isolate

\frac{d t}{d x} : \frac{d t}{d x} = 0

\frac{d t}{d x} = 0

h \to 0 lim ((2 x + h) - 2 x)

cos (\frac{1 - e ^{4 x}}{1 + e ^{4 x}})

\int sin (x^{2} - 5) x d x

y^{^{'}} = x^{\frac{2}{3}}

\int_{1}^{e^{4}} \frac{ln ( x )}{x ^{2}} d x

What is derivative of f(x)=(40t)/(t+2) ?
The answer to derivative of f(x)=(40t)/(t+2) is (dt)/(dx)=0