What is the derivative of ((x^2-4))/x ?

The derivative of ((x^2-4))/x is (x^2+4)/(x^2)

What is the first derivative of ((x^2-4))/x ?

The first derivative of ((x^2-4))/x is (x^2+4)/(x^2)

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derivative of

\frac{( x ^{2} - 4 )}{x}

\frac{x ^{2} + 4}{x ^{2}}

Solution steps

\frac{d}{d x} (\frac{x ^{2} - 4}{x})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ^{2} - 4 ) x - \frac{d x}{d x} ( x ^{2} - 4 )}{x ^{2}}

\frac{d}{d x} (x^{2} - 4) = 2 x

\frac{d x}{d x} = 1

= \frac{2 xx - 1 \cdot ( x ^{2} - 4 )}{x ^{2}}

Simplify

\frac{2 xx - 1 \cdot ( x ^{2} - 4 )}{x ^{2}} : \frac{x ^{2} + 4}{x ^{2}}

= \frac{x ^{2} + 4}{x ^{2}}

\frac{d}{d x} ((ln (x + 1)) 2 - e^{x^{2}})

\int \frac{2}{4 + x ^{2}} d x

y = \frac{1}{x}, y = x, y = 2

\int 2^{x} ln (2) d x

\int x y e^{z} d z

What is the derivative of ((x^2-4))/x ?
The derivative of ((x^2-4))/x is (x^2+4)/(x^2)
What is the first derivative of ((x^2-4))/x ?
The first derivative of ((x^2-4))/x is (x^2+4)/(x^2)