What is the solution for y^'=7y^5 ?

The solution for y^'=7y^5 is y=\sqrt[4]{-1/(4(7t+c_{1))}},y=-\sqrt[4]{-1/(4(7t+c_{1))}}

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y^'=7y^5

y^{^{'}} = 7 y^{5}

y = 4 - \frac{1}{4 ( 7 t + c _{1} )}, y = - 4 - \frac{1}{4 ( 7 t + c _{1} )}

Solution steps

y^{'} (t) = 7 y^{5}

Solve separable ODE:

y = 4 - \frac{1}{4 ( 7 t + c _{1} )}, y = - 4 - \frac{1}{4 ( 7 t + c _{1} )}

y = 4 - \frac{1}{4 ( 7 t + c _{1} )}, y = - 4 - \frac{1}{4 ( 7 t + c _{1} )}

\int \frac{x}{4 + 2 x ^{2}} d x

\frac{d}{d x} (c f (x) + f (x) (c x))

\frac{d}{d x} (\frac{1}{2} ln (x^{2}))

\int \frac{1}{sin ( x ) - cos ( x )} d x

f (x) = 2 x (x^{2} - 4 x + 5)^{6}, at x = 2

What is the solution for y^'=7y^5 ?
The solution for y^'=7y^5 is y=\sqrt[4]{-1/(4(7t+c_{1))}},y=-\sqrt[4]{-1/(4(7t+c_{1))}}