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Popular >

y^{''}+1=0

Solution

y^{^{''}} + 1 = 0

Solution

y = - \frac{t ^{2}}{2} + c_{1} t + c_{2}

Solution steps

y^{''} (t) + 1 = 0

Isolate

y^{''} (t) : y^{''} (t) = - 1

Solve

y^{''} (t) = - 1 : y^{'} (t) = - t + c_{1}

Solve

y^{'} (t) = - t + c_{1} : y = - \frac{t ^{2}}{2} + c_{1} t + c_{2}

y = - \frac{t ^{2}}{2} + c_{1} t + c_{2}

Graph

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Frequently Asked Questions (FAQ)

What is the solution for y^{''}+1=0 ?
The solution for y^{''}+1=0 is y=-(t^2)/2+c_{1}t+c_{2}