What is the integral from 4 to 5 of (tsqrt(t-4)) ?

The integral from 4 to 5 of (tsqrt(t-4)) is 46/15

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integral from 4 to 5 of (tsqrt(t-4))

\int_{4}^{5} (t t - 4) d t

\frac{46}{15}

Decimal

3.06666 \dots

Solution steps

\int_{4}^{5} t t - 4 d t

Apply u-substitution

: \int_{0}^{1} (u + 4) u d u

= \int_{0}^{1} (u + 4) u d u

Expand

(u + 4) u : u^{\frac{3}{2}} + 4 u

= \int_{0}^{1} u^{\frac{3}{2}} + 4 u d u

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} u^{\frac{3}{2}} d u + \int_{0}^{1} 4 u d u

\int_{0}^{1} u^{\frac{3}{2}} d u = \frac{2}{5}

\int_{0}^{1} 4 u d u = \frac{8}{3}

= \frac{2}{5} + \frac{8}{3}

Simplify

\frac{2}{5} + \frac{8}{3} : \frac{46}{15}

= \frac{46}{15}

\int \frac{1}{ln ( t )} d t

\int 15 + 0.55 x d x

\int x^{- \frac{5}{2}} d x

\frac{2 - 3 s}{s ^{2} - 3}

y = (∣ x - 2 ∣)^{3}, y = 8 - 4 x

What is the integral from 4 to 5 of (tsqrt(t-4)) ?
The integral from 4 to 5 of (tsqrt(t-4)) is 46/15