What is the integral from 0 to 0.5 of 2x ?

The integral from 0 to 0.5 of 2x is 0.25

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integral from 0 to 0.5 of 2x

\int_{0}^{0.5} 2 x d x

0.25

Solution steps

\int_{0}^{0.5} 2 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int_{0}^{0.5} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{0.5}

= 2 [\frac{x ^{2}}{2}]_{0}^{0.5}

Simplify

= 2 [0.5 x^{2}]_{0}^{0.5}

Compute the boundaries:

0.125

= 2 \cdot 0.125

Simplify

= 0.25

- 0.04 x^{2} - 0.8 x + 70

\int 1 + 4 t^{2} d t

x \to 2 + lim (\frac{- 5}{x - 2})

x \to - 4 + lim (\frac{3}{x ^{2} - 16})

f (x) = x^{3} - 6 x + 9

What is the integral from 0 to 0.5 of 2x ?
The integral from 0 to 0.5 of 2x is 0.25