What is the derivative of y=cos^3(pit-16) ?

The derivative of y=cos^3(pit-16) is -3picos^2(pit-16)sin(pit-16)

What is the first derivative of y=cos^3(pit-16) ?

The first derivative of y=cos^3(pit-16) is -3picos^2(pit-16)sin(pit-16)

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derivative of

y = cos^{3} (π t - 16)

- 3 π cos^{2} (π t - 16) sin (π t - 16)

Solution steps

\frac{d}{d t} (cos^{3} (π t - 16))

Apply the chain rule:

3 (cos (π t - 16))^{2} \frac{d}{d t} (cos (π t - 16))

= 3 (cos (π t - 16))^{2} \frac{d}{d t} (cos (π t - 16))

\frac{d}{d t} (cos (π t - 16)) = - sin (π t - 16) π

= 3 (cos (π t - 16))^{2} (- sin (π t - 16) π)

Simplify

= - 3 π cos^{2} (π t - 16) sin (π t - 16)

f (x) = x^{4} + 2 x^{2} - x, (1, 2)

\frac{d}{d x} (x, x^{2} - y, x + y^{2})

\int \frac{5}{( 8 z - 1 ) ^{\frac{7}{8}}} d z

e^{2} + ln (4)

x \to 0 - lim (\frac{1}{x})

What is the derivative of y=cos^3(pit-16) ?
The derivative of y=cos^3(pit-16) is -3picos^2(pit-16)sin(pit-16)
What is the first derivative of y=cos^3(pit-16) ?
The first derivative of y=cos^3(pit-16) is -3picos^2(pit-16)sin(pit-16)