What is (\partial)/(\partial y)(3xy+y^2) ?

The answer to (\partial)/(\partial y)(3xy+y^2) is 3x+2y

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(\partial)/(\partial y)(3xy+y^2)

\frac{\partial}{\partial y} (3 x y + y^{2})

3 x + 2 y

Solution steps

\frac{\partial}{\partial y} (3 x y + y^{2})

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (3 x y) + \frac{\partial}{\partial y} (y^{2})

\frac{\partial}{\partial y} (3 x y) = 3 x

\frac{\partial}{\partial y} (y^{2}) = 2 y

= 3 x + 2 y

y = e^{x} + x^{2}

\int \frac{5 e ^{x}}{e ^{2 x} + 2 e ^{x} + 1} d x

(- 4, 0), (1, - 5)

\frac{d}{d x} (x^{2} + 2 y^{2} - 4)

(y - x) d x + 4 x d y = 0

What is (\partial)/(\partial y)(3xy+y^2) ?
The answer to (\partial)/(\partial y)(3xy+y^2) is 3x+2y