What is the derivative of f(x)=(7x+2)/(8x-3) ?

The derivative of f(x)=(7x+2)/(8x-3) is -(37)/((8x-3)^2)

What is the first derivative of f(x)=(7x+2)/(8x-3) ?

The first derivative of f(x)=(7x+2)/(8x-3) is -(37)/((8x-3)^2)

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derivative of

f (x) = \frac{7 x + 2}{8 x - 3}

- \frac{37}{( 8 x - 3 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{7 x + 2}{8 x - 3})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 7 x + 2 ) ( 8 x - 3 ) - \frac{d}{d x} ( 8 x - 3 ) ( 7 x + 2 )}{( 8 x - 3 ) ^{2}}

\frac{d}{d x} (7 x + 2) = 7

\frac{d}{d x} (8 x - 3) = 8

= \frac{7 ( 8 x - 3 ) - 8 ( 7 x + 2 )}{( 8 x - 3 ) ^{2}}

Simplify

\frac{7 ( 8 x - 3 ) - 8 ( 7 x + 2 )}{( 8 x - 3 ) ^{2}} : - \frac{37}{( 8 x - 3 ) ^{2}}

= - \frac{37}{( 8 x - 3 ) ^{2}}

f (x) = \frac{3 x + 4}{3 x - 4}

arcsin (4 x + 1)

\int (sin (2 x))^{3} (cos (2 x))^{2} d x

\int (1 + x^{2}) e^{- x} d x

n = 0 \sum \infty \frac{n}{3 n ^{3} + 1}

What is the derivative of f(x)=(7x+2)/(8x-3) ?
The derivative of f(x)=(7x+2)/(8x-3) is -(37)/((8x-3)^2)
What is the first derivative of f(x)=(7x+2)/(8x-3) ?
The first derivative of f(x)=(7x+2)/(8x-3) is -(37)/((8x-3)^2)