What is the derivative of f(x)=(3x+4)/(3x-4) ?

The derivative of f(x)=(3x+4)/(3x-4) is -(24)/((3x-4)^2)

What is the first derivative of f(x)=(3x+4)/(3x-4) ?

The first derivative of f(x)=(3x+4)/(3x-4) is -(24)/((3x-4)^2)

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derivative of

f (x) = \frac{3 x + 4}{3 x - 4}

- \frac{24}{( 3 x - 4 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{3 x + 4}{3 x - 4})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 3 x + 4 ) ( 3 x - 4 ) - \frac{d}{d x} ( 3 x - 4 ) ( 3 x + 4 )}{( 3 x - 4 ) ^{2}}

\frac{d}{d x} (3 x + 4) = 3

\frac{d}{d x} (3 x - 4) = 3

= \frac{3 ( 3 x - 4 ) - 3 ( 3 x + 4 )}{( 3 x - 4 ) ^{2}}

Simplify

\frac{3 ( 3 x - 4 ) - 3 ( 3 x + 4 )}{( 3 x - 4 ) ^{2}} : - \frac{24}{( 3 x - 4 ) ^{2}}

= - \frac{24}{( 3 x - 4 ) ^{2}}

arcsin (4 x + 1)

\int (sin (2 x))^{3} (cos (2 x))^{2} d x

\int (1 + x^{2}) e^{- x} d x

n = 0 \sum \infty \frac{n}{3 n ^{3} + 1}

\frac{d y}{d x} = \frac{( x + y )}{3 x + 3 y - 4}

What is the derivative of f(x)=(3x+4)/(3x-4) ?
The derivative of f(x)=(3x+4)/(3x-4) is -(24)/((3x-4)^2)
What is the first derivative of f(x)=(3x+4)/(3x-4) ?
The first derivative of f(x)=(3x+4)/(3x-4) is -(24)/((3x-4)^2)