What is the sum from n=0 to infinity of (n!)/(3n!-1) ?

The sum from n=0 to infinity of (n!)/(3n!-1) is diverges

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sum from n=0 to infinity of (n!)/(3n!-1)

n = 0 \sum \infty \frac{n !}{3 n ! - 1}

diverges

Solution steps

n = 0 \sum \infty \frac{n !}{3 n ! - 1}

Apply Series Divergence Test:

diverges

= diverges

e^{x} x - 6 e^{x}

(x^{2} + 1) \frac{d y}{d x} + 3 x (y - 1) = 0, y (0) = 8

\int (x^{5} - 2 x^{3}) d x

y = lo g_{2} (x^{2} - 5 x)

\frac{d}{d x} (arctan (\frac{x}{6}))

What is the sum from n=0 to infinity of (n!)/(3n!-1) ?
The sum from n=0 to infinity of (n!)/(3n!-1) is diverges