What is the solution for (2xy^2+7y)+(2x^2y+7x)y^'=0 ?

The solution for (2xy^2+7y)+(2x^2y+7x)y^'=0 is y=(c_{1})/x

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(2xy^2+7y)+(2x^2y+7x)y^'=0

(2 x y^{2} + 7 y) + (2 x^{2} y + 7 x) y^{^{'}} = 0

y = \frac{c _{1}}{x}

Solution steps

(2 x y^{2} + 7 y) + (2 x^{2} y + 7 x) y^{'} (x) = 0

Solve linear ODE:

y = \frac{c _{1}}{x}

y = \frac{c _{1}}{x}

x^{2} y^{^{''}} + 2 x y^{^{'}} - 2 = 0

\frac{d}{d x} (y^{2} - x^{2})

\frac{\partial}{\partial x} (x^{0.25} y^{0.5})

\frac{d y}{d x} = x - 3

cos (8 t + 2 π)

What is the solution for (2xy^2+7y)+(2x^2y+7x)y^'=0 ?
The solution for (2xy^2+7y)+(2x^2y+7x)y^'=0 is y=(c_{1})/x