What is the sum from n=1 to infinity of 1/n (-1)^n ?

The sum from n=1 to infinity of 1/n (-1)^n is converges

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sum from n=1 to infinity of 1/n (-1)^n

n = 1 \sum \infty \frac{1}{n} (- 1)^{n}

converges

Solution steps

n = 1 \sum \infty \frac{1}{n} (- 1)^{n}

Apply Alternating Series Test:

converges

= converges

- y^{^{''}} + 3 y^{^{'}} = 0

y = 2 x^{2} - 6 x + 6, (1, 2)

\int a^{4 x} d x

\frac{d}{d x} (sin (3 x^{2} - 1))

x \to 0 lim ((1 + x)^{\frac{1}{3 x}})

What is the sum from n=1 to infinity of 1/n (-1)^n ?
The sum from n=1 to infinity of 1/n (-1)^n is converges