What is the solution for y^'=3sqrt(yt) ?

The solution for y^'=3sqrt(yt) is y=t^3+c_{1}t^{3/2}+(c_{1}^2)/4

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y^'=3sqrt(yt)

y^{^{'}} = 3 y t

y = t^{3} + c_{1} t^{\frac{3}{2}} + \frac{c _{1}^{2}}{4}

Solution steps

y^{'} (t) = 3 y t

Solve separable ODE:

y = t^{3} + c_{1} t^{\frac{3}{2}} + \frac{c _{1}^{2}}{4}

y = t^{3} + c_{1} t^{\frac{3}{2}} + \frac{c _{1}^{2}}{4}

\int_{0}^{5} f (x) d x

x \to 0 + lim (\frac{sin ( 2 x )}{x})

\int y^{2} (y + \frac{2}{3}) d y

f (x) = - 4 cos (2 x)

\int - \frac{1}{e ^{x}} d x

What is the solution for y^'=3sqrt(yt) ?
The solution for y^'=3sqrt(yt) is y=t^3+c_{1}t^{3/2}+(c_{1}^2)/4