What is the derivative of f(x)=2x^2-1 ?

The derivative of f(x)=2x^2-1 is 4x

What is the first derivative of f(x)=2x^2-1 ?

The first derivative of f(x)=2x^2-1 is 4x

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derivative of

f (x) = 2 x^{2} - 1

4 x

Solution steps

\frac{d}{d x} (2 x^{2} - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) - \frac{d}{d x} (1)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (1) = 0

= 4 x - 0

Simplify

= 4 x

x \to 0 + lim ((1 + x^{2})^{\frac{1}{x}})

y^{^{''}} + 16 y = cos (4 x) + sin (4 x)

\int + \frac{x ^{2}}{1 - 2 x ^{3}} d x

n = 0 \sum \infty \frac{( n - 1 )}{n}

\int_{1}^{3} (x^{2} - 4 x + 3) d x

What is the derivative of f(x)=2x^2-1 ?
The derivative of f(x)=2x^2-1 is 4x
What is the first derivative of f(x)=2x^2-1 ?
The first derivative of f(x)=2x^2-1 is 4x