What is the integral from-infinity to-3 of xe^x ?

The integral from-infinity to-3 of xe^x is -4/(e^3)

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integral from-infinity to-3 of xe^x

\int_{- \infty}^{- 3} x e^{x} d x

- \frac{4}{e ^{3}}

Decimal

- 0.19914 \dots

Solution steps

\int_{- \infty}^{- 3} x e^{x} d x

Compute the indefinite integral:

\int x e^{x} d x = e^{x} x - e^{x} + C

Compute the boundaries:

\int_{- \infty}^{- 3} x e^{x} d x = - \frac{4}{e ^{3}} - 0

= - \frac{4}{e ^{3}} - 0

Simplify

= - \frac{4}{e ^{3}}

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\frac{d}{d x} (\frac{64 x}{x ^{2} + 64})

\int 4 (1 + tan^{2} (x)) d x

y^{^{''}} + 2 y^{^{'}} = 2 x + 5 - e^{-} 2 x

What is the integral from-infinity to-3 of xe^x ?
The integral from-infinity to-3 of xe^x is -4/(e^3)