What is the solution for e^{x-y}y^'=x-3 ?

The solution for e^{x-y}y^'=x-3 is y=-ln(e^{-x}x-2e^{-x}-c_{1})

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e^{x-y}y^'=x-3

e^{x - y} y^{^{'}} = x - 3

y = - ln (e^{- x} x - 2 e^{- x} - c_{1})

Solution steps

e^{x - y} y^{'} (x) = x - 3

Solve separable ODE:

y = - ln (e^{- x} x - 2 e^{- x} - c_{1})

y = - ln (e^{- x} x - 2 e^{- x} - c_{1})

\frac{\partial}{\partial z} (x^{2} + y^{2} z)

- 8 e^{π - t}

(x^{3} + 2 x^{2})^{- 1}

n = 1 \sum \infty arctan (n + 1)

z \to i lim (z (z + 1))

What is the solution for e^{x-y}y^'=x-3 ?
The solution for e^{x-y}y^'=x-3 is y=-ln(e^{-x}x-2e^{-x}-c_{1})