What is laplacetransform-8e^{pi-t} ?

The answer to laplacetransform-8e^{pi-t} is -(8e^pi)/(s+1)

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laplacetransform-8e^{pi-t}

laplace transform

- 8 e^{π - t}

- \frac{8 e ^{π}}{s + 1}

Solution steps

L {- 8 e^{- t + π}}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= - 8 e^{π} L {e^{- t}}

L {e^{- t}} : \frac{1}{s + 1}

= - 8 e^{π} \frac{1}{s + 1}

Refine

- 8 e^{π} \frac{1}{s + 1} : - \frac{8 e ^{π}}{s + 1}

= - \frac{8 e ^{π}}{s + 1}

(x^{3} + 2 x^{2})^{- 1}

n = 1 \sum \infty arctan (n + 1)

z \to i lim (z (z + 1))

f (x) = ln (4 x + 1)

\frac{d}{d x} (\frac{1}{ln ^{2} ( x )})

What is laplacetransform-8e^{pi-t} ?
The answer to laplacetransform-8e^{pi-t} is -(8e^pi)/(s+1)