What is (\partial)/(\partial x)(36-6x^2-y^2) ?

The answer to (\partial)/(\partial x)(36-6x^2-y^2) is -12x

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(\partial)/(\partial x)(36-6x^2-y^2)

\frac{\partial}{\partial x} (36 - 6 x^{2} - y^{2})

- 12 x

Solution steps

\frac{\partial}{\partial x} (36 - 6 x^{2} - y^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (36) - \frac{\partial}{\partial x} (6 x^{2}) - \frac{\partial}{\partial x} (y^{2})

\frac{\partial}{\partial x} (36) = 0

\frac{\partial}{\partial x} (6 x^{2}) = 12 x

\frac{\partial}{\partial x} (y^{2}) = 0

= 0 - 12 x - 0

Simplify

= - 12 x

\frac{2 x}{e ^{2 x^{2}} - 1}

\frac{d}{d x} (23 sin (x) + 2 cos (x))

\int_{1}^{2} 3 d x

(x^{2} + y^{2})^{2} = 4 x^{2} y, (- 1, 1)

x \to 0 lim (\frac{x + 2}{x})

What is (\partial)/(\partial x)(36-6x^2-y^2) ?
The answer to (\partial)/(\partial x)(36-6x^2-y^2) is -12x