What is the derivative of y=x^3-sqrt(x) ?

The derivative of y=x^3-sqrt(x) is 3x^2-1/(2sqrt(x))

What is the first derivative of y=x^3-sqrt(x) ?

The first derivative of y=x^3-sqrt(x) is 3x^2-1/(2sqrt(x))

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derivative of

y = x^{3} - x

3 x^{2} - \frac{1}{2 x}

Solution steps

\frac{d}{d x} (x^{3} - x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (x)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (x) = \frac{1}{2 x}

= 3 x^{2} - \frac{1}{2 x}

f (x) = cos (4 t + 12)

x \to 0 lim (\frac{y ^{1 - x}}{1 - x})

y^{^{''}} - 6 y^{^{'}} + 2 y = 0, y (0) = 0, y^{^{'}} (0) = 1

x \to 5 lim (x^{2} + 4)

\int \frac{3 x ^{2} - 3}{x ^{3} - 3 x} d x

What is the derivative of y=x^3-sqrt(x) ?
The derivative of y=x^3-sqrt(x) is 3x^2-1/(2sqrt(x))
What is the first derivative of y=x^3-sqrt(x) ?
The first derivative of y=x^3-sqrt(x) is 3x^2-1/(2sqrt(x))