What is the solution for x(dy)/(dx)=y(y+1) ?

The solution for x(dy)/(dx)=y(y+1) is y=(e^{c_{1}}x)/(1-e^{c_{1)}x}

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x(dy)/(dx)=y(y+1)

x \frac{d y}{d x} = y (y + 1)

y = \frac{e ^{c_{1}} x}{1 - e ^{c_{1}} x}

Solution steps

x \frac{d y}{d x} = y (y + 1)

Solve separable ODE:

y = \frac{e ^{c_{1}} x}{1 - e ^{c_{1}} x}

y = \frac{e ^{c_{1}} x}{1 - e ^{c_{1}} x}

f (x) = \frac{6 x}{x + 2}, (4, 4)

f (x) = - \frac{1}{6} (x^{- 6} + x^{12})

\frac{x ^{2} - 36}{x - 6}

y^{^{''}} + y = sin (2 x)

\frac{d}{d x} ((2 x^{2} - 1) + (5 x - 6))

What is the solution for x(dy)/(dx)=y(y+1) ?
The solution for x(dy)/(dx)=y(y+1) is y=(e^{c_{1}}x)/(1-e^{c_{1)}x}