What is the solution for y^{''}+1/4 y=0 ?

The solution for y^{''}+1/4 y=0 is y=c_{1}cos(t/2)+c_{2}sin(t/2)

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y^{''}+1/4 y=0

y^{^{''}} + \frac{1}{4} y = 0

y = c_{1} cos (\frac{t}{2}) + c_{2} sin (\frac{t}{2})

Solution steps

y^{''} (t) + \frac{1}{4} y = 0

Solve linear ODE:

y = c_{1} cos (\frac{t}{2}) + c_{2} sin (\frac{t}{2})

y = c_{1} cos (\frac{t}{2}) + c_{2} sin (\frac{t}{2})

x \to - 4 lim (3)

x \to \infty lim (\frac{1}{lo g _{2} ( x )})

\int_{- 1}^{0} \frac{1}{x ^{2}} d x

\frac{4 s e ^{- 4 s}}{2 s ^{2} + 50}

\frac{s + 1}{s ^{2} + s + 1}

What is the solution for y^{''}+1/4 y=0 ?
The solution for y^{''}+1/4 y=0 is y=c_{1}cos(t/2)+c_{2}sin(t/2)