en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

d/(du)(u^3-5u^2+7/(3u^2)+6)

Solution

\frac{d}{d u} (u^{3} - 5 u^{2} + \frac{7}{3 u ^{2}} + 6)

Solution

3 u^{2} - 10 u - \frac{14}{3 u ^{3}}

Solution steps

\frac{d}{d u} (u^{3} - 5 u^{2} + \frac{7}{3 u ^{2}} + 6)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d u} (u^{3}) - \frac{d}{d u} (5 u^{2}) + \frac{d}{d u} (\frac{7}{3 u ^{2}}) + \frac{d}{d u} (6)

\frac{d}{d u} (u^{3}) = 3 u^{2}

\frac{d}{d u} (5 u^{2}) = 10 u

\frac{d}{d u} (\frac{7}{3 u ^{2}}) = - \frac{14}{3 u ^{3}}

\frac{d}{d u} (6) = 0

= 3 u^{2} - 10 u - \frac{14}{3 u ^{3}} + 0

Simplify

= 3 u^{2} - 10 u - \frac{14}{3 u ^{3}}

Graph

Popular Examples

(\partial)/(\partial x)(10990+1120x+873y)

\frac{\partial}{\partial x} (10990 + 1120 x + 873 y)

tangent of sqrt(5x+1)tangent of

5 x + 1

integral of (4+3x)/(1+x^2)

\int \frac{4 + 3 x}{1 + x ^{2}} d x

integral of (e^{-2x})/(x^2)

\int \frac{e ^{- 2 x}}{x ^{2}} d x

integral from 0 to pi/3 of sec^4(x)

\int_{0}^{\frac{π}{3}} sec^{4} (x) d x

Frequently Asked Questions (FAQ)

What is the d/(du)(u^3-5u^2+7/(3u^2)+6) ?
The d/(du)(u^3-5u^2+7/(3u^2)+6) is 3u^2-10u-(14)/(3u^3)
What is the first d/(du)(u^3-5u^2+7/(3u^2)+6) ?
The first d/(du)(u^3-5u^2+7/(3u^2)+6) is 3u^2-10u-(14)/(3u^3)