What is the tangent of sqrt(5x+1) ?

The tangent of sqrt(5x+1) is y= 5/(2sqrt(5a_{0)+1)}x+sqrt(5a_{0)+1}-(5a_{0})/(2sqrt(5a_{0)+1)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of sqrt(5x+1)

tangent of

5 x + 1

y = \frac{5}{2 5 a _{0} + 1} x + 5 a_{0} + 1 - \frac{5 a _{0}}{2 5 a _{0} + 1}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 5 a_{0} + 1)

Find the slope of

y = 5 x + 1 : \frac{d y}{d x} = \frac{5}{2 5 x + 1}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{5}{2 5 a _{0} + 1}

Find the line with slope m=

\frac{5}{2 5 a _{0} + 1}

and passing through

(a_{0}, 5 a_{0} + 1) : y = \frac{5}{2 5 a _{0} + 1} x + 5 a_{0} + 1 - \frac{5 a _{0}}{2 5 a _{0} + 1}

y = \frac{5}{2 5 a _{0} + 1} x + 5 a_{0} + 1 - \frac{5 a _{0}}{2 5 a _{0} + 1}

\int \frac{4 + 3 x}{1 + x ^{2}} d x

\int \frac{e ^{- 2 x}}{x ^{2}} d x

\int_{0}^{\frac{π}{3}} sec^{4} (x) d x

f (x) = 8 - x^{2}

\int u^{1} d u

What is the tangent of sqrt(5x+1) ?
The tangent of sqrt(5x+1) is y= 5/(2sqrt(5a_{0)+1)}x+sqrt(5a_{0)+1}-(5a_{0})/(2sqrt(5a_{0)+1)}