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Popular >

y^'=y-t^2+1

Solution

y^{^{'}} = y - t^{2} + 1

Solution

y = t^{2} + 2 t + 1 + c_{1} e^{t}

Solution steps

y^{'} (t) = y - t^{2} + 1

Solve linear ODE:

y = t^{2} + 2 t + 1 + c_{1} e^{t}

y = t^{2} + 2 t + 1 + c_{1} e^{t}

Graph

Popular Examples

sum from n=4 to infinity of (7^n)/(14^n)

n = 4 \sum \infty \frac{7 ^{n}}{1 4 ^{n}}

implicit (dy)/(dx),x=sec(4y)implicit derivative

\frac{d y}{d x}, x = sec (4 y)

derivative of (x^2+3(x^2-2)^8)

\frac{d}{d x} ((x^{2} + 3) (x^{2} - 2)^{8})

4sin(x)sin(y)+cos(y)y^'=0

4 sin (x) sin (y) + cos (y) y^{^{'}} = 0

tangent of f(x)=4x^2+12x+5,\at (-1)tangent of

f (x) = 4 x^{2} + 12 x + 5, at (- 1)

Frequently Asked Questions (FAQ)

What is the solution for y^'=y-t^2+1 ?
The solution for y^'=y-t^2+1 is y=t^2+2t+1+c_{1}e^t