What is the derivative of y=5e^x+7ln(x) ?

The derivative of y=5e^x+7ln(x) is 5e^x+7/x

What is the first derivative of y=5e^x+7ln(x) ?

The first derivative of y=5e^x+7ln(x) is 5e^x+7/x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

y = 5 e^{x} + 7 ln (x)

5 e^{x} + \frac{7}{x}

Solution steps

\frac{d}{d x} (5 e^{x} + 7 ln (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (5 e^{x}) + \frac{d}{d x} (7 ln (x))

\frac{d}{d x} (5 e^{x}) = 5 e^{x}

\frac{d}{d x} (7 ln (x)) = \frac{7}{x}

= 5 e^{x} + \frac{7}{x}

\frac{\partial}{\partial x} (1 + x^{3} + x^{4})

\frac{d}{d x} (\frac{7}{x ^{2} - x + 2})

y^{^{''}} - y^{^{'}} - 6 y = 2 e^{t} - t^{2} - 2 t + 3

\int 20 - 0.1

\frac{d}{d y} (4 e^{2 y} (2 x^{2} + 4 x + 2 y + 1))

What is the derivative of y=5e^x+7ln(x) ?
The derivative of y=5e^x+7ln(x) is 5e^x+7/x
What is the first derivative of y=5e^x+7ln(x) ?
The first derivative of y=5e^x+7ln(x) is 5e^x+7/x