What is the d/(dt)(-e^{3t}) ?

The d/(dt)(-e^{3t}) is -e^{3t}*3

What is the first d/(dt)(-e^{3t}) ?

The first d/(dt)(-e^{3t}) is -e^{3t}*3

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\frac{d}{d t} (- e^{3 t})

- e^{3 t} \cdot 3

Solution steps

\frac{d}{d t} (- e^{3 t})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{d}{d t} (e^{3 t})

Apply the chain rule:

e^{3 t} \frac{d}{d t} (3 t)

= e^{3 t} \frac{d}{d t} (3 t)

\frac{d}{d t} (3 t) = 3

= - e^{3 t} \cdot 3

\int 6 x^{2} cos (x) d x

f (x) = x^{3} - 3 x + 2, at x = 2

\frac{\partial}{\partial y} (2 e^{2 z} x y - 2 y)

\frac{1}{x ^{3}}

\frac{d}{d t} (cos (t) - sin (t))