What is the derivative of f(x)=(-x^2-9)/((x^2-9)^2) ?

The derivative of f(x)=(-x^2-9)/((x^2-9)^2) is -(2x(-x^2-27))/((x^2-9)^3)

What is the first derivative of f(x)=(-x^2-9)/((x^2-9)^2) ?

The first derivative of f(x)=(-x^2-9)/((x^2-9)^2) is -(2x(-x^2-27))/((x^2-9)^3)

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derivative of

f (x) = \frac{- x ^{2} - 9}{( x ^{2} - 9 ) ^{2}}

- \frac{2 x ( - x ^{2} - 27 )}{( x ^{2} - 9 ) ^{3}}

Solution steps

\frac{d}{d x} (\frac{- x ^{2} - 9}{( x ^{2} - 9 ) ^{2}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( - x ^{2} - 9 ) ( x ^{2} - 9 ) ^{2} - \frac{d}{d x} ( ( x ^{2} - 9 ) ^{2} ) ( - x ^{2} - 9 )}{( ( x ^{2} - 9 ) ^{2} ) ^{2}}

\frac{d}{d x} (- x^{2} - 9) = - 2 x

\frac{d}{d x} ((x^{2} - 9)^{2}) = 4 x (x^{2} - 9)

= \frac{( - 2 x ) ( x ^{2} - 9 ) ^{2} - 4 x ( x ^{2} - 9 ) ( - x ^{2} - 9 )}{( ( x ^{2} - 9 ) ^{2} ) ^{2}}

Simplify

\frac{( - 2 x ) ( x ^{2} - 9 ) ^{2} - 4 x ( x ^{2} - 9 ) ( - x ^{2} - 9 )}{( ( x ^{2} - 9 ) ^{2} ) ^{2}} : - \frac{2 x ( - x ^{2} - 27 )}{( x ^{2} - 9 ) ^{3}}

= - \frac{2 x ( - x ^{2} - 27 )}{( x ^{2} - 9 ) ^{3}}

2 x^{2}, at x = 1

\int_{3}^{\infty} e^{- 2 x} d x

\int e^{- s x} \cdot x d x

f (x) = \frac{x ^{2} - 9}{x ^{2} + 3 x}

y = x, y = 2 x 100 - x^{2}

What is the derivative of f(x)=(-x^2-9)/((x^2-9)^2) ?
The derivative of f(x)=(-x^2-9)/((x^2-9)^2) is -(2x(-x^2-27))/((x^2-9)^3)
What is the first derivative of f(x)=(-x^2-9)/((x^2-9)^2) ?
The first derivative of f(x)=(-x^2-9)/((x^2-9)^2) is -(2x(-x^2-27))/((x^2-9)^3)