What is the tangent of 2x^2,\at x=1 ?

The tangent of 2x^2,\at x=1 is y=4x-2

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tangent of 2x^2,\at x=1

tangent of

2 x^{2}, at x = 1

y = 4 x - 2

Solution steps

Find the tangent point:

(1, 2)

Find the slope of

y = 2 x^{2} : \frac{d y}{d x} = 4 x

Compute the slope of

y = 2 x^{2}

x = 1 : m = 4

Find the line with slope m=

4

and passing through

(1, 2) : y = 4 x - 2

y = 4 x - 2

\int_{3}^{\infty} e^{- 2 x} d x

\int e^{- s x} \cdot x d x

f (x) = \frac{x ^{2} - 9}{x ^{2} + 3 x}

y = x, y = 2 x 100 - x^{2}

f (x) = 186.7