What is the sum from n=1 to infinity of (5n)/(2n+1) ?

The sum from n=1 to infinity of (5n)/(2n+1) is diverges

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sum from n=1 to infinity of (5n)/(2n+1)

n = 1 \sum \infty \frac{5 n}{2 n + 1}

diverges

Solution steps

n = 1 \sum \infty \frac{5 n}{2 n + 1}

Apply the constant multiplication rule:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= 5 \cdot n = 1 \sum \infty \frac{n}{2 n + 1}

Apply Series Divergence Test:

diverges

= 5 diverges

= diverges

\frac{d}{d x} (18 + x)

\int \frac{3 x + 1}{x ^{2} + 3 x - 10} d x

\frac{8 e ^{2 w} + 3 e ^{w}}{e ^{w}}

\int \frac{3 x ^{2} + 5 x - 4}{( x ^{2} - 1 ) ( x + 1 )} d x

What is the sum from n=1 to infinity of (5n)/(2n+1) ?
The sum from n=1 to infinity of (5n)/(2n+1) is diverges