What is the solution for y^'=5y+y^5 ?

The solution for y^'=5y+y^5 is y=\sqrt[4]{5/(e^{-20t-c_{1)}-1}},y=-\sqrt[4]{5/(e^{-20t-c_{1)}-1}}

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y^'=5y+y^5

y^{^{'}} = 5 y + y^{5}

y = 4 \frac{5}{e ^{- 20 t - c_{1}} - 1}, y = - 4 \frac{5}{e ^{- 20 t - c_{1}} - 1}

Solution steps

y^{'} (t) = 5 y + y^{5}

Solve Bernoulli ODE:

y = 4 \frac{5}{e ^{- 20 t - c_{1}} - 1}, y = - 4 \frac{5}{e ^{- 20 t - c_{1}} - 1}

y = 4 \frac{5}{e ^{- 20 t - c_{1}} - 1}, y = - 4 \frac{5}{e ^{- 20 t - c_{1}} - 1}

\frac{d}{d x} (\frac{x ^{2}}{3 x + 7})

y = \frac{1}{f ( x )}

x^{\frac{1}{3}} - 1

\frac{d}{d t} (\frac{1}{( t + 1 ) ^{2}})

\int 3 x y^{2} d y

What is the solution for y^'=5y+y^5 ?
The solution for y^'=5y+y^5 is y=\sqrt[4]{5/(e^{-20t-c_{1)}-1}},y=-\sqrt[4]{5/(e^{-20t-c_{1)}-1}}