What is the derivative of A/(y^{10)}+Be^y ?

The derivative of A/(y^{10)}+Be^y is -(10A)/(y^{11)}+Be^y

What is the first derivative of A/(y^{10)}+Be^y ?

The first derivative of A/(y^{10)}+Be^y is -(10A)/(y^{11)}+Be^y

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derivative of

\frac{A}{y ^{10}} + B e^{y}

- \frac{10 A}{y ^{11}} + B e^{y}

Solution steps

\frac{d}{d y} (\frac{A}{y ^{10}} + B e^{y})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d y} (\frac{A}{y ^{10}}) + \frac{d}{d y} (B e^{y})

\frac{d}{d y} (\frac{A}{y ^{10}}) = - \frac{10 A}{y ^{11}}

\frac{d}{d y} (B e^{y}) = B e^{y}

= - \frac{10 A}{y ^{11}} + B e^{y}

y = x + 1, y = x^{2} - 1

\int \frac{x ^{2} - x + 30}{x ^{3} + 5 x} d x

\frac{\partial}{\partial x} (cos (w + x) sin (y - z))

\frac{d}{d t} (3 t - 2)

\int_{0}^{1} \frac{1}{( x + 1 ) ( x + 2 )} d x

What is the derivative of A/(y^{10)}+Be^y ?
The derivative of A/(y^{10)}+Be^y is -(10A)/(y^{11)}+Be^y
What is the first derivative of A/(y^{10)}+Be^y ?
The first derivative of A/(y^{10)}+Be^y is -(10A)/(y^{11)}+Be^y